MATH SOLVE

2 months ago

Q:
# Please help quick A rectangular garden has length twice as great as is width a second rectangular has the same length as the first garden and width that is 4 meters greater than width of the first garden the second garden has area of 120 square meters what is the length of the two gardens?

Accepted Solution

A:

First garden information: let w = the width of the garden, then 2w = the length of the garden.

Second garden information:

(w + 4) = the width and 2w = the length; the area is equal to 120

Now taking the information of the second garden we can set up the following equation: 2w(w + 4) = 120 or the following quadratic 2w² + 8w - 120 = 0

Now solving this quadratic by factoring we see that the solutions are:

w = -10 and w = 6 ... of these two solutions only w = 6 makes sense.

With w = 6, the length of the two gardens would be 12

Second garden information:

(w + 4) = the width and 2w = the length; the area is equal to 120

Now taking the information of the second garden we can set up the following equation: 2w(w + 4) = 120 or the following quadratic 2w² + 8w - 120 = 0

Now solving this quadratic by factoring we see that the solutions are:

w = -10 and w = 6 ... of these two solutions only w = 6 makes sense.

With w = 6, the length of the two gardens would be 12