Q:

A minor league baseball team plays 128 games a seanson. If the tam won 16 more than three times as many games as they lost how many wins and losses did the team have.

Accepted Solution

A:
Answer: The team won 100 games and losses 28 gamesStep-by-step explanation:Let the number of games won denoted by x and the games lost is denoted by y .Given : A minor league baseball team plays 128 games in a season. Team won 16 more than three times as many games as they lost.Then, the system of equations, we have[tex]x+y=128-------(1)\\\\x=3y+16------------(2)[/tex]We can rewrite equation (2) as [tex]x-3y=16----------------(3)[/tex]Now, Eliminate equation (3) from (1), we get[tex]y-(-3y)=128-16\\\\\Rightarrow\ 4y=112\\\\\Rightarrow\ y=\dfrac{112}{4}=28[/tex]Substitute the value of y in (2), we get[tex]x=3(28)+16=84+16=100[/tex]Hence, the team won 100 games and losses 28 games.