A store sells cans of paint for $8 each, and brushes for $12 each. If they sell 100 items, andmake $880, how many cans and brushes did they sell?A60 cans, 30 brushesB80 cans, 20 brushesC40 cans, 40 brushesD20 cans, 50 brushes

Answer:B.) 80 cans, 20 brushesStep-by-step explanation:Let the cans of paint be represented by variable p , and brushes by variable bThe first equation would be ; p + b = 100p = 100 - bThe second equation would be;8p + 12b = 880Replace p in the equation by (100-b);=8(100-b) + 12b =880=800 - 8b +12b = 880= subtract  800 from both sides to get;4b = 880-8004b = 80divide both sides by 4 to solve for b;b= 80/4b = 20If p + b = 100, then p+20 = 100p = 100-20p = 80Therefore, they sold 80 cans of paint and 20 brushes